Henry C. Adams

Capitolo 92

= 84.719. Then 1.389 + 84.719 = 86.108--says, 86.11 fts;  but the
head of acutal is 20.42 fts, and the flow approximately varies as
the square root of the head, so that the true flow will be
around

[* The mathematics:  $15,555 * \ sqrt{\frac{20.42}{86.11} = 7574.8 $]

[The illustration: the Fig tree 34 Diagram that Illustrates the Calculations For The
DISCHARGES OF OUTFALLS MARITTIMO]

--says 7,575 braids. But a flow of 15,555 braids for minute is
in demand, as various approximately as the fifth power of the
diameter, the in demand diameter will be around

[* The mathematics:  \ the sqrt[5]{\frac{30^5 \ it calculates 15,555}{7575}] = 34.64
thumbs.

Now supposes a diameter of 40 in, and repeats the calculations.
Then the head necessary to produce the speed

[* The mathematics:  = \ the frac{15,555^2}{215 \ it calculates 40^4}] = 0.044 fts, and
you lead to overcome the attrition =

[* The mathematics:  \ the frac{15,555^2 \ it calculates 2042}{240 \ it calculates 40^5}]

= 20.104 fts Then 0.044 + 20.104 = 20.148, say 20.15 fts and the
the true flow will be therefore around

[* The mathematics:  15,555 * \ sqrt{\frac{20.42}{20.15}}]

= 15,659 braids and the in demand diameter around

[* The mathematics:  \ the sqrt[5]{\frac{40^5 * 15,555}{15,659}}]

= 39.94 thumbs.

When, therefore, a 30 in pipe of diameter are presumed a diameter,
of 34.64 in you/he/she has shown for being in demand, and when 40 in it is presumed
39.94 in it is suitable.


Makes _a_ = the difference among the two false diameters. _b_ =
increase found on lower diameter. _c_ = decrease founded under
greater diameter. _d_ = you lower false diameter.


Then the true diameter =

[* The mathematics:  d + \ the frac{ab}{b+c} = 30 + \ the frac{10 \ the times
4.64}{4.64+0.06} = 30 + \ frac{46.4}{4.7} = 39.872],

or, says, 40 in that it equalizes the in demand diameter.

A simpler way to reach the ransom would be to calculate him/it
from the formula of Ripple of Saint for unloaded of sewer, or rather the speed
standing per second =

[* The mathematics:  124 \ the sqrt[3]{R^2} \ the sqrt{S}],