Henry C. Adams

Capitolo 91

times--while the pomps are working to their greatest power in
torrential sewage in the reservoir during the whole one of the
period;  then when the valves are closed the wish of reservoir
is empty, and his/her available whole ability for deposit up to that
the valves are open again.

To take a concrete example, supposes that the reservoir and
outfall is built as shown in Fig tree. 34, and that it is
forced to know the diameter of pipe of outfall when the
reservoir contains 1,000,000 braids and the whole one some pomps
together included some that can be staid down to face some,
increase of the population in the future, can deliver 600,000
braids for now. When the reservoir is full the water of top
level will be 43.00 O.Ds., but to have a border for
contingencies and to leave space to the loss in head owed to entrance of
sewage in the pipe, for the attrition in to pass around curves and
for a disdains reduction in to discharge ability of the pipe from
reason for incrustation, will be desirable to take the
reservoir as height, but it supposes that sewage is to the level
31.00. Water's head in the sea measured above of the centre
of the pipe 21 fts will be, so that

[* The mathematics:  $21 \ it calculates 1/3 $],

or 7 in--says, 0.58 fts--it has to be assistant to the height of tall
you sprinkle, while reducing so the real head from 31.00 - 10.00 =
21.00 to 20.42 fts You quantity to be low will be

[* The mathematics:  $\ the frac{1,000,000 + (3 * 600,000)} {3} $]

= 933,333 braids for now = 15,555 braids for minute, or,
6.23 braids that you/they take equalize to 1 cubic foot, the quantity equalizes
2,497 cubic feet for min Suppose the in demand diameter to be 30
in, then, from the formula of Hawksley, the head necessary to production
speed =

[* The mathematics:  $\ the frac{Gals. for min^2}{215 \ diameter of times in
inches^4} = \ the frac{15,555^2}{215 * 30^4} $]

 = 1.389 fts and the head to overcome the attrition =

[* The mathematics:  $\ the frac{Gals. for min^2 \ times Length in yards}{240 *
diameter in inches^5} = \ the frac{15,555^2 * 2042}{240 * 30^5}]